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(Comments by Sorab R. Vatcha dt 09-07-2025 )

Here are two other different ways to express three fractions containing just the nine digits to have a sum of 1:

5/6 + 2/14 + 9/378 = 1

8/9 + 3/54 + 7/126 = 1

Both of these equations have one digit in the first denominator, two digits in the second, and three in the third. These are probably the only two equations with this additional condition. Perhaps there are others without this condition.

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(Comments by Al Zimmermann dt 04-05-2017 )

The decimal expansions for 1/27 and 1/37 are as shown above because 27 × 37 = 999.
Another example would be:
1/271 = .00369 00369 00369 …
1/369 = .00271 00271 00271 …
because 271 × 369 = 99999.

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(Comments by Al Zimmermann dt 01-05-2017 )

This fraction contains Fibonacci numbers up to 3 digits in length.
This can be generalized as follows::
The fraction 1/(10^2n-10^n-1) contains Fibonacci numbers up to n digits in length.
If n = 3, the fraction is 1 / (1000000 – 1000 – 1) = 1/998999.
For n = 4, the fraction is 1/99989999 = .0000000100010002000300050008001300210034005500890144….
The n leading zeroes in the decimal expansion can be considered the 0th term in the Fibonacci series or they can be removed by changing the fractions numerator to 10^n:
10000/99989999 = .000100010002000300050008001300210034005500890144….

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